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$e^{\mathrm{i}\pi}+1=0$

$\begin{aligned} ans&=114514\\ &=1919810 \end{aligned}$

$\omega_n^{\pm 1}=\cos\left(\cfrac{2\pi}{n}\right)\pm\sin\left(\cfrac{2\pi}{n}\right)\text{i}\tag{2,8}$

$F(x)=F_l\left(x^2\right)+xF_r\left(x^2\right)\tag{3}$

$\begin{aligned} F\left(\omega_n^k\right)&=F_l\left(\omega_{n/2}^k\right)+\omega_n^k F_r\left(\omega_{n/2}^k\right) \\ F\left(\omega_n^{n/2+k}\right)&=F_l\left(\omega_{n/2}^k\right)-\omega_n^k F_r\left(\omega_{n/2}^k\right) \end{aligned}\tag{4,5}$

$Y_j=F\left(\omega_n^j\right)=\sum_{k=0}^{n-1}\left(\omega_n^j\right)^k\times F[k]\tag{6}$

$F[i]=\cfrac{1}{n}\sum_{j=0}^{n-1}\left(\omega_n^{-i}\right)^j\times Y_j\tag{7}$

---

#include <iostream>

int main()
{
	printf("Hello World");
	return 0;
}

code

sout

洛谷

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114514

• [x] 114514
• [ ] 1919810

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Here is a simple flow chart:

graph TD;
    A-->B;
    A-->C;
    B-->D;
    C-->D;